Program in the C programming language to find the product or multiplication of two matrices. Below is the C program to multiply two matrices –
/* C program to multiply the two matrices */ #include <stdio.h> #include<conio.h> void main() { int m, n, p, q, c, d, k, sum = 0; int ar1[10][10], ar2[10][10], mul[10][10]; printf("Enter the number of rows and columns of first matrix\n"); scanf("%d%d", &m, &n); printf("Enter the elements of first matrix\n"); for ( c = 0 ; c < m ; c++ ) { for ( d = 0 ; d < n ; d++ ) { scanf("%d", &ar1[c][d]); } } printf("Enter the number of rows and columns of second matrix\n"); scanf("%d%d", &p, &q); if ( n != p ) { printf("Multiplication is not possible of the two matrices \n"); } else { printf("Enter the elements of second matrix\n"); for ( c = 0 ; c < p ; c++ ) { for ( d = 0 ; d < q ; d++ ) { scanf("%d", &ar2[c][d]); } } for ( c = 0 ; c < m ; c++ ) { for ( d = 0 ; d < q ; d++ ) { for ( k = 0 ; k < p ; k++ ) { sum = sum + ar1[c][k]*ar2[k][d]; } mul[c][d] = sum; sum = 0; } } printf("Product of entered matrices:-\n"); for ( c = 0 ; c < m ; c++ ) { for ( d = 0 ; d < q ; d++ ) printf("%d\t", mul[c][d]); printf("\n"); } } getch(); }
Output –
Enter the number of rows and columns of first matrix – 2 2
Enter the elements of first matrix –
2 3
4 3
Enter the number of rows and columns of second matrix – 2 3
5 7 2
5 6 4
Product of entered matrices is –
25 32 16
35 46 20
simplify this program
I appreciate your posts on this and a simalir post on 3/24/2010.Here is my scenario, I have two columns. I need to add the first columns (the easy part). The second column is a percent that I need to subtract by 100 then multiply against $1 for each line, then sum themHere is the input:942330863 96942172150 95942099452 92I need this as an output:2826602465 160169797I tried this code, but it’s just doing the percentage work and only doing it for the first line and not summing every line.awk ‘BEGIN {FS=”,”} NR == 1{ n1 = $1; x = substr((100-$2)/100,2,3); y = x*$2; next } { n1 += $1; y += $y }END { printf (“%-15d%d\n”,n1,y) }’
Spero di riuscire ad andarlo a vedere. Lo Spiderman degli anni '70 l'avevo visto e forse proprio all'epoca inizia a collezionare fumetti che fino ad allora avevo solo letto saltuariamente.
OcchiGrazie Andrea, ho letto e l’ho trovato interessante. So che Paolo certe cose non può dirle chiaramente, si sconfina dai fatti nella politica. Viene quasi da pensare che popski e iltremendo abbiano ragione, i complottisti sono un complotto organizzato da Bush per passare sotto silenzio gli errori compiuti e la vulnerabilità degli USA. ARG! Sono diventato un complottista anch’io! 😉
Multiplying two matrix is a O(n^3) algorithm but we also have an algorithm called strasen algorithm which does it in O(n^2.8).
Utrolig bra bilde …. og for en skjønnhet! Jeg har noen som svermer rundt mine søyleblomster, men som for deg, de flyr fort til neste blomst nÃ¥r jeg nærmer meg med kameraet :o)
This info is the cat’s pajamas!
Visste inte att det hade kommit ett Ferrari-DLC till Need for Speed Shift, får väl bara hoppas jag råkar vara den utvalda att lyckas få denna kod :)//axelflensburg@hotmail.com
What an exciting year full of changes!And someone called you a running snob? YOU? Couldn’t be MORE wrong. What a horrible thing to say. Who are are they, I’ll go “tweet” them up! :o)Here’s to a fabulous 2011 – you are going to ROCK IT in typical Chic Runner style!